QQ:
2020-08-12
确实,进入胶着期后,胜负常常取决于细微差别。给你一套快速判断框架,帮你看清争冠走向:
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你可以先做这三步小测:
如果你愿意,我可以用你给的三到四支球队及其剩余赛程,做一个简短的模拟(含头对头规则),或直接写个小脚本跑1万次蒙特卡洛,输出各队夺冠概率、预期积分和关键转折点。示例代码草图(可按你提供的数据填充):
# quick_scudetto_sim.pyimport math, random# 简化版:用赛季场均进失球估计泊松强度,主场优势=+0.25球TEAMS = { # 'Team': {'att': goals_for_per_game, 'def': goals_against_per_game} 'TeamA': {'att': 1.8, 'def': 0.9}, 'TeamB': {'att': 1.7, 'def': 1.0}, 'TeamC': {'att': 1.6, 'def': 0.95},}FIXTURES = [ # (home, away, played?), 填入剩余赛程,已赛不填 ('TeamA', 'TeamB', False), ('TeamC', 'TeamA', False), ('TeamB', 'TeamC', False),
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]BASE_POINTS = {'TeamA': 68, 'TeamB': 67, 'TeamC': 66} # 当前积分def pois(lam): # 采样泊松分布的简单方法
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L, k, p = math.exp(-lam), 0, 1.0 while p [[NEWS.CONTENT_HTML]]gt; L: k += 1 p *= random.random() return k - 1def match_points(h, a): # 简化主场优势:主队进球期望+0.25 lam_h = max(0.05, TEAMS[h]['att'] * a_to_d(TEAMS[a]['def']) + 0.25) lam_a = max(0.05, TEAMS[a]['att'] * a_to_d(TEAMS[h]['def'])) gh, ga = pois(lam_h), pois(lam_a) if gh [[NEWS.CONTENT_HTML]]gt; ga: return (3, 0) if gh [[NEWS.CONTENT_HTML]]lt; ga: return (0, 3) return (1, 1)def a_to_d(x): # 将失球强度映射为抑制系数(粗略) return 1.0 / (1.0 + (x - 1.0)*0.8)def sim_once(): pts = BASE_POINTS.copy() for h, a, played in FIXTURES: ph, pa = match_points(h, a) pts[h] += ph; pts[a] += pa # 头对头同分时这里可接入相互战绩表;先用总进球差代理 best = max(pts.values()) leaders = [t for t, p in pts.items() if p == best] return leaders, ptsdef run(n=10000): win = {t:0 for t in TEAMS} avg = {t:0.0 for t in TEAMS} for _ in range(n): leaders, pts = sim_once() for t in TEAMS: avg[t] += pts[t] # 平分按均摊,或在此加入相互战绩判定 share = 1.0/len(leaders) for t in leaders: win[t] += share for t in TEAMS: avg[t] /= n win[t] = round(100*win[t]/n, 1) return win, {t: round(avg[t],1) for t in TEAMS}if __name__ == [[NEWS.CONTENT_HTML]]quot;__main__[[NEWS.CONTENT_HTML]]quot;: win, avg = run() print([[NEWS.CONTENT_HTML]]quot;Win%:[[NEWS.CONTENT_HTML]]quot;, win) print([[NEWS.CONTENT_HTML]]quot;ExpPts:[[NEWS.CONTENT_HTML]]quot;, avg)告诉我目前卷入争冠的具体球队、当前积分差和剩余3–5轮的关键对手,我可以立刻替你跑一版预测,或按你的口径(更保守或更激进)调参给出结论与看点。
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